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       Home    Astronomy    How to compute the position of the
Sun    Sun, Moon
& Earth Applet  
       Daylight Applet
       
      How to compute the length
of a day
        
      
        
       
      The following calculation gives an approximate value for the
length of a day from sunrise to sunset (duration of daylight) for any
location.  
      A screen shot of Walter Fendts applet
shows the "nautical triangle" of the celestial sphere for an observer
located at O: North Pole NP, Zenith Ze and
star or sun St. 
The angles in this triangle are: NP-Ze = 90° - beta, NP-St =
90° - delta, Ze-St = 90° - h  
       
         
      
      
        
          
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            h
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             altitude (elevation) of the
sun  
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            beta
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             geogr. latitude of the
observer 
N: beta > 0°, S: beta < 0°  
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            delta
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             declination of the sun 
measured in degrees north and south of the celestial equator 
N: 0° < delta < 23.5°, S: 0° > delta > -
23.5°  
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            tau
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             local hour angle of the
sun (Greenwich hour angle +/- longitude), 
measured along the equator from the meridian
S-NP-N of the observer to the hour circle
SP-St-NP of the star St.  
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      From spherical trigonometry we get:  
      sin (h) = sin (beta) * sin (delta)   + cos (beta) *
cos (delta) * cos (tau)
      At sunrise / sunset, with sin (h)=0 and dividing by cos
(beta)*cos (delta) we get:  
      cos (tau) = - tan (beta)*tan (delta)
      For |- tan(beta)*tan(delta)| > 1 there is no sunrise or
sunset (length of day 0 hours or 24 hours ).  
      We can approximate the declination of the sun by:  
      delta = 23.5° * sin [(x/365)*360°]
      with x = number of days since vernal equinox (about March 21)  
        
       
         
June 21, local hour angle tau for sunset
in Vienna at 20:58 local time.
      Example 1:  
      June 21, delta=23.5°, beta=48° (Vienna), we get tau =
118.9° 
corresponding to 7.93 hours (since tau=360° corresponds to 24 hours) 
The Sun rises 7.93 hours before transit (culmination) and sets 7.93
hours after, 
length of solar day is 15,85 hours, 
exact value (from "Sun, Moon & earth Applet") is: 16.07 hours.  
         
      Example 2:  
      December 21, delta=-23.5°, beta=48° (Vienna), we get
tau = 61.1° 
corresponding to 4.07 hours (since tau=360° corresponds to 24 hours) 
Sun rises 4.07 hours before transit (Culmination) and sets 4.07 hours
after, 
length of solar day is 8.15 hours, 
exact value is: 8.36 hours.  
         
       
        
       
      More precise calculation by
my JavaScript 
      
         
       
        
         
      Last
Modified: 2008, Jan 02 
      
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